## May 02, 2020

### #LeetCode: Jewels and Stones

You're given strings J representing the types of stones that are jewels, and S representing the stones you have.  Each character in S is a type of stone you have.  You want to know how many of the stones you have are also jewels.

The letters in J are guaranteed distinct, and all characters in J and S are letters. Letters are case sensitive, so "a" is considered a different type of stone from "A".

Example 1:
Input: J = "aA", S = "aAAbbbb"
Output: 3

Example 2:
Input: J = "z", S = "ZZ"
Output: 0

Note:
• S and J will consist of letters and have length at most 50.
• The characters in J are distinct.
Algorithm
1). If the length of either J or S is 0, return 0.
2). Create a set and add all the Jewels in it by iterating J.
3). numberOfStones is the count of Stones which are also jewels.
4). Now we start iterating the stones we have (i.e S) and check if the stone is present in jewel set, if yes increment numberOfStones.
5). Return the numberOfStones.

Java Solution:

ALSO CHECK: Other LeetCode Solutions in Java

-K Himaanshu Shuklaa..